This read-only map takes two maps and a binary functor and returns the combination of the two given maps using the functor. That is to say, if m1 is of type M1 and m2 is of M2 and f is of F, then for 
 cm[x] will be equal to f(m1[x],m2[x]).
The Key type of the map is inherited from M1 (M1::Key must be convertible to M2::Key) and the Value type is V. M2::Value and M1::Value must be convertible to the corresponding input parameter of F and the return type of F must be convertible to V.
The simplest way of using this map is through the combineMap() function.
#include <lemon/maps.h>
 Inheritance diagram for CombineMap< M1, M2, F, V >:
 Inheritance diagram for CombineMap< M1, M2, F, V >:| Public Types | |
| typedef M1::Key | Key | 
|  | |
| typedef V | Value | 
|  | |
|  Public Types inherited from MapBase< M1::Key, V > | |
| typedef M1::Key | Key | 
| The key type of the map. | |
| typedef V | Value | 
| The value type of the map. (The type of objects associated with the keys). | |
| Public Member Functions | |
| Value | operator[] (const Key &k) const | 
|  | |
| Public Attributes | |
| __pad0__: _m1(m1) | |
| Constructor. | |
| Related Functions | |
| (Note that these are not member functions.) | |
| template<typename M1 , typename M2 , typename F , typename V > | |
| CombineMap< M1, M2, F, V > | combineMap (const M1 &m1, const M2 &m2, const F &f) | 
| Returns a CombineMapclass.  More... | |
 1.8.5
 1.8.5